101 B
101 B
4.14MHz\
\frac1{2\pi f_rC}=\frac1{2\pi (4.14MHz)(82pF)}=468\Omega\
{2k\Omega\over468\Omega}
4.14MHz\
\frac1{2\pi f_rC}=\frac1{2\pi (4.14MHz)(82pF)}=468\Omega\
{2k\Omega\over468\Omega}